正切半角公式

而被称为萬能公式的原因是利用 $\tan {\frac {\alpha }{2}}$ 的代換可以解決一些有關三角函数的積分。参见三角换元法。

{\begin{aligned}\tan \left({\frac {\eta }{2}}\pm {\frac {\theta }{2}}\right)&={\frac {\sin \eta \pm \sin \theta }{\cos \eta +\cos \theta }}=-{\frac {\cos \eta -\cos \theta }{\sin \eta \mp \sin \theta }},\\[10pt]\tan \left(\pm {\frac {\theta }{2}}\right)&={\frac {\pm \sin \theta }{1+\cos \theta }}={\frac {\pm \tan \theta }{\sec \theta +1}}={\frac {\pm 1}{\csc \theta +\cot \theta }},~~~~(\eta =0)\\[10pt]\tan \left(\pm {\frac {\theta }{2}}\right)&={\frac {1-\cos \theta }{\pm \sin \theta }}={\frac {\sec \theta -1}{\pm \tan \theta }}=\pm (\csc \theta -\cot \theta ),~~~~(\eta =0)\\[10pt]\tan \left({\frac {\pi }{4}}\pm {\frac {\theta }{2}}\right)&={\frac {1\pm \sin \theta }{\cos \theta }}=\sec \theta \pm \tan \theta ={\frac {\csc \theta \pm 1}{\cot \theta }},~~~~(\eta ={\frac {\pi }{2}})\\[10pt]\tan \left({\frac {\pi }{4}}\pm {\frac {\theta }{2}}\right)&={\frac {\cos \theta }{1\mp \sin \theta }}={\frac {1}{\sec \theta \mp \tan \theta }}={\frac {\cot \theta }{\csc \theta \mp 1}},~~~~(\eta ={\frac {\pi }{2}})\\[10pt]{\frac {1-\tan {\frac {\theta }{2}}}{1+\tan {\frac {\theta }{2}}}}&={\sqrt {\frac {1-\sin \theta }{1+\sin \theta }}}.\end{aligned}}

正切半角公式，又称万能公式，这一组公式有四个功能：

因此，这组公式被称为以切表弦公式，简称以切表弦。它们是由二倍角公式求得的。

\sin \alpha ={\frac {2\tan {\frac {\alpha }{2}}}{1+\tan ^{2}{\frac {\alpha }{2}}}}

\cos \alpha ={\frac {1-\tan ^{2}{\frac {\alpha }{2}}}{1+\tan ^{2}{\frac {\alpha }{2}}}}

\tan \alpha ={\frac {2\tan {\frac {\alpha }{2}}}{1-\tan ^{2}{\frac {\alpha }{2}}}}

\cot \alpha ={\frac {1-\tan ^{2}{\frac {\alpha }{2}}}{2\tan {\frac {\alpha }{2}}}}

\sec \alpha ={\frac {1+\tan ^{2}{\frac {\alpha }{2}}}{1-\tan ^{2}{\frac {\alpha }{2}}}}

\csc \alpha ={\frac {1+\tan ^{2}{\frac {\alpha }{2}}}{2\tan {\frac {\alpha }{2}}}}

万能公式的证明

\sin \alpha =2\sin {\frac {\alpha }{2}}\cos {\frac {\alpha }{2}}={\frac {2\sin {\frac {\alpha }{2}}\cos {\frac {\alpha }{2}}}{\cos ^{2}{\frac {\alpha }{2}}+\sin ^{2}{\frac {\alpha }{2}}}}={\frac {2\sin {\frac {\alpha }{2}}\cos {\frac {\alpha }{2}}\div \cos ^{2}{\frac {\alpha }{2}}}{(\cos ^{2}{\frac {\alpha }{2}}+\sin ^{2}{\frac {\alpha }{2}})\div \cos ^{2}{\frac {\alpha }{2}}}}={\frac {2{\frac {\sin {\frac {\alpha }{2}}}{\cos {\frac {\alpha }{2}}}}}{1+{\frac {\sin ^{2}{\frac {\alpha }{2}}}{\cos ^{2}{\frac {\alpha }{2}}}}}}={\frac {2\tan {\frac {\alpha }{2}}}{1+\tan ^{2}{\frac {\alpha }{2}}}}

$\tan \alpha ={\frac {2\tan {\frac {\alpha }{2}}}{1-\tan ^{2}{\frac {\alpha }{2}}}}$

再由同角三角函数间的关系，得出

\cos \alpha ={\frac {\sin \alpha }{\tan \alpha }}={\frac {\frac {2\tan {\frac {\alpha }{2}}}{1+\tan ^{2}{\frac {\alpha }{2}}}}{\frac {2\tan {\frac {\alpha }{2}}}{1-\tan ^{2}{\frac {\alpha }{2}}}}}={\frac {1-\tan ^{2}{\frac {\alpha }{2}}}{1+\tan ^{2}{\frac {\alpha }{2}}}}

正切半角公式的几何证明

在单位圆内，t = tan(φ/2)。根据相似关係， ${\frac {t}{\sin \phi }}={\frac {1}{1+\cos \phi }}$ ，可得出

t={\frac {\sin \phi }{1+\cos \phi }}={\frac {\sin \phi (1-\cos \phi )}{(1+\cos \phi )(1-\cos \phi )}}={\frac {1-\cos \phi }{\sin \phi }}

。

显然 $\tan {\frac {a+b}{2}}={\frac {\sin {\frac {a+b}{2}}}{\cos {\frac {a+b}{2}}}}={\frac {\sin a+\sin b}{\cos a+\cos b}}$ 。

此公式亦可以对双曲函数起到类似的作用，由双曲线右支上的一点(cosh θ, sinh θ)给出。从(−1, 0)到y轴给出了如下等式：

t=\tanh {\tfrac {1}{2}}\theta ={\frac {\sinh \theta }{\cosh \theta +1}}={\frac {\cosh \theta -1}{\sinh \theta }}

可以得到

和

e^{\theta }={\frac {1+t}{1-t}},

e^{-\theta }={\frac {1-t}{1+t}}.

卡尔·维尔斯特拉斯引入这个式子来省去查找原函数的麻烦。

θ在T而得出下面的双曲反正切函數和自然对数之间的关系：

\operatorname {artanh} t={\frac {1}{2}}\ln {\frac {1+t}{1-t}}.

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